X^2+22x+118=0

Solution for X^2+22x+118=0 equation:

X^2+22X+118=0

a = 1; b = 22; c = +118;
Δ = b2-4ac
Δ = 222-4·1·118
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2\sqrt{3}}{2*1}=\frac{-22-2\sqrt{3}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2\sqrt{3}}{2*1}=\frac{-22+2\sqrt{3}}{2}
$